a) Ta có: \(A=1\dfrac{1}{4}\cdot x^3y\cdot\left(-\dfrac{6}{7}xy^5\right)^0\cdot\left(-2\dfrac{2}{3}xy\right)\)

\(=\dfrac{5}{4}x^3y\cdot\dfrac{-8}{3}xy\)

\(=\left(\dfrac{5}{4}\cdot\dfrac{-8}{3}\right)\cdot\left(x^3\cdot x\right)\cdot\left(y\cdot y\right)\)

\(=\dfrac{-10}{3}x^4y^2\)

\(A=\left(-\dfrac{2}{3}x^3y^4\right)^2.\left(-3x^5y^2\right)^3\)

\(A=\left(\dfrac{4}{9}x^6y^8\right).\left(-27x^{15}y^6\right)\)

\(A=\left(\dfrac{4}{9}.-27\right)\left(x^6.x^{15}\right)\left(y^8.y^{16}\right)\)

\(A=-12x^{21}y^{24}\)

\(\text{Hệ số:-12}\)

\(\text{Bậc:45}\)

\(B=\left(3x^2y\right).\left(-\dfrac{1}{3}x^3y\right).\left(-\dfrac{1}{4}x^3y^4\right)\)

\(B=\left(3.-\dfrac{1}{3}.-\dfrac{1}{4}\right).\left(x^2.x^3.x^3\right).\left(y.y.y^4\right)\)

\(B=\dfrac{1}{4}x^8y^6\)

\(\text{Hệ số:}\dfrac{1}{4}\)

\(\text{Bậc:14}\)

a, (-3a⁶)(-1/2a³)x⁸y⁶

-Hệ số: (-3a⁶)(-1/2a³)

-Biến: x⁸y⁶

b, -Bậc: 14.

1. 

Tại x = -1, có : 

2.(-1)² - 5.(-1) + 2 

= 2.1 + 5 + 2 

= 9 

Tại x = \(\dfrac{1}{2}\), có : 

\(2.\left(\dfrac{1}{2}\right)^2-5.\dfrac{1}{2}+2\)

= \(2.\dfrac{1}{4}-2,5+2\)

= 0,5 - 2,5 + 2

= 0

2. 

\(\dfrac{1}{2}xy^2.\left(-3xyz\right).2x^2z\)

= -3x⁴y³z²

- Hệ số : -3

- Bậc : 9

thay x =-1 vào bt ta được

\(2\left(-1\right)^2-5\left(-1\right)+2=2+5+2=9\)

thay x=1/2 vào bt ta được 

\(2.\left(\dfrac{1}{2}\right)^2-5.\dfrac{1}{2}+2=\dfrac{1}{2}-\dfrac{5}{2}+\dfrac{4}{2}=0\)

\(\dfrac{1}{2}xy^2.-3xyz.2x^2z=-3x^4y^3z\)²

hệ số là -3 bậc 9

\(2,\\ a,=-3x^3y^3z^4\\ b,=\dfrac{1}{4}xy^2\cdot\dfrac{1}{4}x^4y^4\cdot\left(-\dfrac{4}{5}yz^2\right)=-\dfrac{1}{20}x^5y^7z^2\\ c,=-\dfrac{15}{14}x^6y^{11}z^{10}\\ 3,\\ a,=9\left(-1\right)\left(-\dfrac{1}{27}\right)=\dfrac{1}{3}\\ b,=-\dfrac{1}{5}\left(-8\right)=\dfrac{8}{5}\\ c,=\dfrac{4}{9}a\cdot36\left(-1\right)=-16a\)

a: M=A*B=1/4*a^2*x^2y^6*(-27)a^6x^6

=-27/4a^8*x^8*y^6

Hệ số là -27/4a^8

Biến là x^8;y^6

b: bậc là 14

a) \(\left( {\dfrac{1}{2}{x^3}} \right).\left( -{4{x^2}} \right) = \left( {\dfrac{1}{2}.(-4)} \right).\left( {{x^3}.{x^2}} \right) = (-2).{x^5}\).

Hệ số: -2

Bậc: 5

b) \(\dfrac{1}{2}{x^3} - \dfrac{5}{2}{x^3} = \left( {\dfrac{1}{2} - \dfrac{5}{2}} \right){x^3} = \dfrac{{ - 4}}{2}.{x^3} =  - 2{x^3}\)

Hệ số: -2

Bậc: 3

\(a,\left(\dfrac{1}{2}x^3\right).\left(-4x^2\right)=\left(-4.\dfrac{1}{2}\right).\left(x^3.x^2\right)=-2x^5\\ Hệ.số:-2;bậc:5\\ b,\dfrac{1}{2}x^3-\dfrac{5}{2}x^3=-2x^3\\ Hệ.số:-2;bậc:3\)

\(a,5x^2y^3z.\left(-11\right)xyz^4=-55x^3y^4z^5\)

Biến : x³y⁴z⁵

Hệ số:-55

Bậc:12

b, \(-6x^4y^4\left(-\dfrac{2}{3}\right)x^5y^3z^2=4x^9y^7z^2\)

Biến : x⁹y⁷z²

Hệ số:4

Bậc:18

\(a)\left(5x^2y^3z\right).\left(-11xyz^4\right)=-55x^3y^4z^5.\)

- Biến: \(x;y;z.\)

- Hệ số: \(-55.\)

- Bậc: \(5.\)

\(b)\left(-6x^4y^4\right).\left(-\dfrac{2}{3}x^5y^3z^2\right)=4x^9y^7z^2.\)

- Biến: \(x;y;z.\)

- Hệ số: \(4.\)

- Bậc: \(9.\)